assume a general exponential growth/decay model. A population of pigeons numbers 1,000 on the fifth day and 1,200 on the tenth day. What will it number on the twentieth day?
a. 1,600
b. 1,728
c. 2,074
d. 1,546

Question

assume a general exponential growth/decay model. A population of pigeons numbers 1,000 on the fifth day and 1,200 on the tenth day. What will it number on the twentieth day?
  a. 1,600 	
b. 1,728 	
c. 2,074 	
d. 1,546

anonymous · Answer

we can do this almost instantly 
$$P(t)=1000\times (1.2)^{\frac{t}{5}}$$

anonymous · Answer

the $1.2$ from $\frac{1200}{100}$ and the $5$ i the denominator of the exponent because it grows by a factor of $1.2$ in 5 days

anonymous · Answer

$$P(7)=1000\times (1.2)^{\frac{7}{5}}$$ http://www.wolframalpha.com/input/?i=1000%281.2^%287%2F5%29%29