Question

Probability: How many odd 3 digit positive integers can be written using the digits 2, 3, 4, 5, and 6?

Answer 1

the last digit must be one of 3 or 5, so there are 2 ways
the first and the second digit can selected of all numbers (i assumed the repetitions is allowed)
so, it is 5 x 5 x 2 = 50 ways

Answer 2

how did you get 3 or 5 as the last digit?

Answer 3

because to get an odd number :)

Answer 4

right! okay thanks! :)

Answer 5

very welcome :)