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Mathematics 9 Online
OpenStudy (anonymous):

Can someone help me change rectangular coordinates to polar?

OpenStudy (anonymous):

\[\left( -3,-3\sqrt{3} \right)\]

OpenStudy (anonymous):

can you find r here?

OpenStudy (anonymous):

\(\large r=\sqrt{x^2+y^2} \)

OpenStudy (anonymous):

that helps, how would I find theta? since polar is (r,theta)

OpenStudy (anonymous):

ok... according to the point that is given, what quadrant is it in?

OpenStudy (anonymous):

3

OpenStudy (anonymous):

so find a theta that satisfies that?

OpenStudy (anonymous):

yes.. use \(\large \theta = arctan \frac{y}{x} \)

OpenStudy (anonymous):

can you show me how you got that arctan equation I know its used to find the inverse of tan but can you show me a step before that?

OpenStudy (anonymous):

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