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Can someone help me change rectangular coordinates to polar?
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\[\left( -3,-3\sqrt{3} \right)\]
can you find r here?
\(\large r=\sqrt{x^2+y^2} \)
that helps, how would I find theta? since polar is (r,theta)
ok... according to the point that is given, what quadrant is it in?
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3
so find a theta that satisfies that?
yes.. use \(\large \theta = arctan \frac{y}{x} \)
can you show me how you got that arctan equation I know its used to find the inverse of tan but can you show me a step before that?
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