Question

Help

Answer 1

Question please :D

Answer 2

\[\frac{ 2a ^{2}-4a+2 }{ 3m-9 }\]

Answer 3

What do you need to factor?

Answer 4

If you mean factorize, I'd guess you need to factorize 2a^2-4a+2
You'll be wanting to take out the common factor of 2 from the top and then factorize the rest to get 2(a-1)(a-1)
In equation form:
\[\frac{ 2a^2-4a+2 }{ 3m-9 }=\frac{ 2(a^2-2a+1) }{ 3m-9 }=\frac{ 2(a-1)(a-1) }{ 3(m-3) }\]
I also removed a constant from the bottom. You can also write it as (a-1)^2