Ask
your own question, for FREE!
Mathematics
8 Online
OpenStudy (anonymous):
Let f be the function defined above. Which of the following statements about f are true?
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
f(x)= (x^2 - 4)/(x-2) if x cannot equal 2
1 if x = 2
OpenStudy (anonymous):
I. f has a limit at x = 2
II. f is continuous at x = 2
III. f is differentiable at x = 2
OpenStudy (anonymous):
I know II. is untrue :)
OpenStudy (anonymous):
@electrokid
OpenStudy (anonymous):
@agent0smith
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
step 1) find the left hand side limit
step 2) find the right hand side limit.
show, then we proceed
OpenStudy (anonymous):
idk what you mean
OpenStudy (anonymous):
to check if the limit exists, we have to check the right hand side and the left hand side limits (one sided limits)
OpenStudy (anonymous):
\[\Large{\text{left hand side limit:}\lim_{x\to2^-}f(x)\\
\text{right hand side limit:}\lim_{x\to2^+}f(x)
}\]
OpenStudy (anonymous):
so in this case x^-4/(x-2) f does not have a lim at x=2
Join the QuestionCove community and study together with friends!
Sign Up
OpenStudy (anonymous):
why not?
OpenStudy (anonymous):
so it does exist?
OpenStudy (anonymous):
why does it? :D
we have to check...
we first have to find the individual left hand side and right hand side limits
OpenStudy (anonymous):
|dw:1367719858631:dw|
left hand side -> x comes close to 2 but is less than 2
right hand side -> x comes close to 2 but is greater than 2
Can't find your answer?
Make a FREE account and ask your own questions, OR help others and earn volunteer hours!
Join our real-time social learning platform and learn together with your friends!
Latest Questions
Mari103:
CLOSED.
2 hours ago
3 Replies
0 Medals
clllaaaaaire:
CLOSED
2 weeks ago
0 Replies
0 Medals