Let f be the function defined above. Which of the following statements about f are true?
f(x)= (x^2 - 4)/(x-2) if x cannot equal 2 1 if x = 2
I. f has a limit at x = 2 II. f is continuous at x = 2 III. f is differentiable at x = 2
I know II. is untrue :)
@electrokid
@agent0smith
step 1) find the left hand side limit step 2) find the right hand side limit. show, then we proceed
idk what you mean
to check if the limit exists, we have to check the right hand side and the left hand side limits (one sided limits)
\[\Large{\text{left hand side limit:}\lim_{x\to2^-}f(x)\\ \text{right hand side limit:}\lim_{x\to2^+}f(x) }\]
so in this case x^-4/(x-2) f does not have a lim at x=2
why not?
so it does exist?
why does it? :D we have to check... we first have to find the individual left hand side and right hand side limits
|dw:1367719858631:dw| left hand side -> x comes close to 2 but is less than 2 right hand side -> x comes close to 2 but is greater than 2
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