1. Consider three position vectors (tails are the origin): →− u =⟨1,0,0⟩ →− v =⟨4,0,2⟩ →− w = ⟨0, 1, 1⟩ (a) Find an equation of the plane passing through the tips of u , v , and w . (b) Find an equation of the line perpendicular to the plane from part (a) and passing through the origin. Part (a) normal vector is Not understanding how to use (0,0,0) to find line equation for part b Also equation of plane is -2(x-1)-5(y-0)+3(z-0)=0

Question

1. Consider three position vectors (tails are the origin):
→− u =⟨1,0,0⟩
→− v =⟨4,0,2⟩
→− w = ⟨0, 1, 1⟩
(a) Find an equation of the plane passing through the tips of u , v , and w .
 (b) Find an equation of the line perpendicular to the plane from part (a) and passing
through the origin.

Part (a) normal vector is <-2,-5,3>
Not understanding how to use (0,0,0) to find line equation for part b
 Also equation of plane is -2(x-1)-5(y-0)+3(z-0)=0

anonymous · Answer

??? was having login in issues...

loser66 · Answer

ok, show me your work in part a)

anonymous · Answer

take The cross product of uv X uw to find the normal vector V
so cross product is |dw:1368063746848:dw|

anonymous · Answer

so equation is -2(x-1)-5(y-0)+3(z-0)=0 by the formula

anonymous · Answer

i do the cross product in detail but too long to write

loser66 · Answer

so, for part a, your equation should be 2x +5y -3z =2, right?