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if \[\int\limits_{0}^{a}(4-2x).dx =4 \] find a
the integral is 4x - x^2 from 0 to a. do you know how to plug in the limits?
I think so don't u just substitute?
yes. if the integrand is f'(x) and the integral which we found is f(x). to plug in the limits from a to b you do f(b) - f(a)
= 4(a) - (a)^2 - 4(0) - (0)^2 = 4
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solve for a :)
4a - a^2 = 4 a-a^2 = 1 = -a(1-a) X = o or -1
a^2 - 4a + 4 = 0
(a-2)^2 = 0 sorry for delay of replying. was doing own homework and forgot
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