Question

what is the vertex of the graph of y=2x^@+4x-5 a)(2,11) b) (1,) c) (0,-5) d) (-1,-7)

Answer 1

@skinny23 @Eyad @amistre64 @hartnn some one help please

Answer 2

the quadratic in this form-- ax^2+bx+c

uses the formula -b/2a
so from your equation :
a=2 and b = 4
so,
-(4)/2(2)= -4/4= -1
now plug back in -1
2(-1) ^2+ 4(-1) -5
2-4-5 = -7
your vertex is at
-1,-7

Answer 3

heres anopther one y=-2x^2+8x+9 a)(2,17) b)(1,15) c)(0,9) d)
(-1,-1)

Answer 4

@zpupster

Answer 5

again just try plugging in
a = -2
b= 8
use the formula for finding x value of vertex (or usually they use h)
-b/2a
-(8)/2(-2) = -8/-4= 2
I will let you plug that in the formula to get the y (or k value)