Question

In radioactive decay series, what is the particle or element of each in of following? Describe types of radiation given off in this series.
1. 92238U  A + 24He
2. A  91234Pa + B
3. 91234Pa  C + –10e
4. C  90230Th + 24He
5. 90230Th  D + 24He
6. D  86222Rn + E
7. 86222Rn  84218Po + F
8. 84218Po  G + 24He
9. G  83214Bi + H
10. 83214Bi  I + –10e
11. I  J + 24He

Answer 1

There's \(\alpha\)-decay. These are Helium particles \(\to \begin{matrix}4\\
2\end{matrix}He\)

Then you have \(\beta\)-decay. These are electrons \(\to \begin{matrix}~~~0\\ -1\end{matrix}e\)

Don't know what particles in 2,6,7 and 9.

You can write the nuclear equations easy in \(\LaTeX\):
\(\begin{matrix}168\\ 77\end{matrix}Ir\to \begin{matrix}4\\ 2\end{matrix}He+\begin{matrix}164\\ 75\end{matrix}Re\)

This is the code:
`\(\begin{matrix}168\\ 77\end{matrix}Ir\to \begin{matrix}4\\ 2\end{matrix}He+\begin{matrix}164\\ 75\end{matrix}Re\)`


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