Question

Find all solutions in the interval [0, 2π).

sec2 x - 2 = tan2 x

I'm not sure how to do this, could someone walk me through?

Answer 1

\[sec^2 x-2=tan^2 x?\]

Answer 2

or sec (2x) -2 = tan (2x)?

Answer 3

the first one :)

Answer 4

no solution, friend. since 1+ tan^2 x = sec^2 x ---> 2 + tan^2 x = 1+ 1 + tan^2x = 1 + sec^2x = sec^2x leads to 0=1 ( therefore, no solution)

Answer 5

oh ok i see now, thank you!