Question

Consider the line that passes through the point (3, -6) and has a slope of 4.

Part 1: Write the equation of this line using point-slope form. (2 points)
Part 2: Using your equation from part 1, rewrite this equation in slope-intercept form. Make sure to show all of your work. (2 points)
Part 3: Using your equation from part 2, rewrite this equation in standard form. Make sure to show all of your work. (2 points)

Thanks a lot

Answer 1

eq of the line having slope m and passing through pt (x1,y1) in point-slope form is given by
y-y1=m(x-x1)

Answer 2

here slope is 4 and x1=3 and y1=-6

Answer 3

no i still don't understand i have done read the lesson multiple times and i don't understand

Answer 4

see slope is the tangent of the inclination angle which the given line makes with the +ve direction of x-axis

Answer 5

so the equation would be y-6=4(x-3)

Answer 6

for part a)
eq f the reqd line is
y-(-6)=4(x-3)

Answer 7

u did it correctly except y+6 instead of y-6

Answer 8

okay

Answer 9

i know slope intercept is y=mx+b

Answer 10

but how do you get read of the x1 and y1

Answer 11

rid

Answer 12

x1,y1 is the cordinate of the point through which the line passes

Answer 13

right but that is not in y=mx+b

Answer 14

y=mx+ b is the slope-interept form

Answer 15

yes but it says make the first equation into slope intercept form

Answer 16

after simplifying just rearrange the terms keeping y on the left side of equal sign

Answer 17

y+6=4(x-3)
y+6=4x-12
y=4x-18
is that right

Answer 18

y-(-6)=4(x-3)
or y+6= 4x -12
y=4x-12-6
y=4x-18 (point slope form)

Answer 19

right

Answer 20

okay i think i got in now so for standard form
y=4x-18
-4x+y=-18

Answer 21

also for standard form just rearrange the terms
u may write 4x-y-18=0 or 4x-y=18 as per ur choice

Answer 22

wait for the second one how come your 4x isn't negative