Question

Solve using the Quadratic Formula.

4x² + 7x + 1 = 0

Answer 1

Please help!! this test is determing if i pass or not

Answer 2

\[4x^2 + 7x + 1 = 0\]
Written in
\[ax^2+bx+c=0\]
The quadratic formula is
\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}\]
substitute in the values
a is 4
b is 7
c is 1

Answer 3

A moment.

Answer 4

Im still confused!

Answer 5

What exactly is your point of confusion? Do you not understand how to evaluate the formula, or how it is derived, or ???

Answer 6

laziness

Answer 7

am i sopose to plug in those values and no im not lazy when i ask question i need help not to answer them for me

Answer 8

Substitute the respective formulas in the equation,it's the simplest.

Answer 9

.Sam. gave you the formula, and told you to substitute the numbers for each letter (even identifying the values of each letter).

Answer 10

Your equation is \(4x^2+7x+1=0\) so \(a = 4, b = 7, c = 1\) and the formula is
\[x = \frac{-b\pm\sqrt{b^2-4ac}}{2a}\]
Wherever you see \(a\) substitute 4; \(b\) substitute 7; \(c\) substitute 1

Answer 11

ok and i got -7+ or - \[\sqrt{33}\] over 8

Answer 12

Very good...

Answer 13

thank you..see im not lazy i just need some help i didnt ask for the answer i asked you to help me

Answer 14

x = 1/8 (-7-sqrt(33))

Answer 15

I didn't accuse you of laziness, I just asked what was confusing you...

@Odero there are two solutions because the polynomial has an x^2 term. the other solution is x = 1/8(-7+sqrt(33))

Answer 16

Ooops,thanks...