math hw question

Question

math hw question

luigi0210 · Answer

Difference of two perfect squares..
(x-9)(x+9)

luigi0210 · Answer

(s-9)(s+9)

luigi0210 · Answer

only if I get a medal.. haha jk sure :P

anonymous · Answer

sorry lol i thought i gave you one

luigi0210 · Answer

Well first we have to get the c term by using (b/2)^2
$$(-\frac{ 6 }{ 2 })^2=9$$
So now add that to both sides:
$$(x^2-6x+9)=-8+9$$
Simplify: $$(x-3)^2=1$$

luigi0210 · Answer

Now take the square root of both sides:
$$\sqrt{(x-3)^2}=\pm \sqrt{1}$$
Since the square root of 1 is 1 we leave it:
$$x-3= \pm1$$
Now add 3:
$$x-3+3=\pm1+3$$
$$x=\pm1+3$$
Separate and do then separately:
$$x=1+3=4$$
$$x-1+3=2$$ 

And there you go :)

anonymous · Answer

oh wow you make it easy thanks for showing me how you do it not i will be able to do the rest on my own thanks so much :)

luigi0210 · Answer

No problem, happy to help :D