Question

math hw question

Answer 1

Difference of two perfect squares..
(x-9)(x+9)

Answer 2

(s-9)(s+9)

Answer 3

only if I get a medal.. haha jk sure :P

Answer 4

sorry lol i thought i gave you one

Answer 5

Well first we have to get the c term by using (b/2)^2
\[(-\frac{ 6 }{ 2 })^2=9\]
So now add that to both sides:
\[(x^2-6x+9)=-8+9\]
Simplify: \[(x-3)^2=1\]

Answer 6

Now take the square root of both sides:
\[\sqrt{(x-3)^2}=\pm \sqrt{1}\]
Since the square root of 1 is 1 we leave it:
\[x-3= \pm1\]
Now add 3:
\[x-3+3=\pm1+3\]
\[x=\pm1+3\]
Separate and do then separately:
\[x=1+3=4\]
\[x-1+3=2\]

And there you go :)

Answer 7

oh wow you make it easy thanks for showing me how you do it not i will be able to do the rest on my own thanks so much :)

Answer 8

No problem, happy to help :D