Question

4x+12 over x^2-2x multiplied by x over 6x+18

Answer 1

\[\frac{ 4x+12 }{ x ^{2}-2x }\times \frac{ x }{ 6x+18 }\]

Answer 2

\[=\]...

Answer 3

@Forever_Me @Jhannybean @RANE @kausarsalley

Answer 4

Show all work, please and thank you ;3

Answer 5

do a little factoring

\[\frac{4(x + 3)}{x(x -2)} \times \frac{x}{3(x + 3)}= \frac{ (x + 3) \times x \times 4}{(x + 3)\times x \times (x -2) \times 3}\]

I've rearranged things so that you can see the common factors.

whats left after removing the common factors in the answer.

Answer 6

Could you simplfy it? Or show how?

Answer 7

ok whats common in the numerator and the denominator..?

Answer 8

3

Answer 9

not quite you have (x + 3) and x that are in the top and bottom of the fraction.

so what is left if you take them out of the fraction..?

Answer 10

Oh, ok. 4?

Answer 11

you will have 4 in the top, now what about the bottom of the fraction

take out (x + 3) and x... whats left...?

Answer 12

(x-2)

Answer 13

and something else.. is left...

Answer 14

x or the normal 3?

Answer 15

just the 3

so you are left with

in compact form

\[\frac{4x(x+ 3)}{3x(x+3)(x-2)} = \frac{4}{3(x - 2)}\]

you could distribute the denominator for an answer as well

Answer 16

Ok, like distribut the 4 over 3(x-2) o the other one?

Answer 17

@campbell_st
isn't it supposed to be 6(x+3) as your denominator (look at first step)

Answer 18

??

Answer 19

I got \[\frac{ 2 }{ 3(x-2) }\] for a final answer..

Answer 20

you are right

Answer 21

So it's not what @campbell_st came up with?

Answer 22

i am sure because of the little mistake he made in the 1st step...

Answer 23

......what he got is wrong

Answer 24

oops I made a mistake

its should be

\[\frac{4}{6(x -2)}\]

which gives your answer... which is correct.

just distribute the denominator

\[\frac{2}{3x -6}\]

Answer 25

Okay, but everything else is right?

Answer 26

well in the 1st factorised step you get

\[\frac{4x(x + 3)}{6x(x+3)(x-2)}\]

which gives your answer... then can be expanded as above.

Answer 27

is this right for number 11?

Answer 28

yep its a solution... you may need the factorised step above... but it depends on what your teacher wants.

Answer 29

@campbell_st please give @kausarsalley a medal

Answer 30

ok where should i pput that astep?

Answer 31

Where do i put that step @campbell_st ?