Question

JK, KL, and LJ are all tanget to O (not drawn to scale). JA = 12, AL = 15, and CK = 5. Find the perimeter of triangle JKL. How would I do this?

Answer 1

perimeter = length around the triangle

Answer 2

= JL + LK + KJ

= JA + AL + AC + CK + KB + BJ

Answer 3

plugin

JA = BJ
AL = AC
CK = KB

(why ?)

Answer 4

= 2(JA + AL + CK)
= 2(12 + 15 + 5)

Answer 5

So the answer would be 64?

Answer 6

yes