Solve the equation by using the quadratic formula:

4b^2 + 8b = 4

Question

Solve the equation by using the quadratic formula:

4b^2 + 8b = 4

anonymous · Answer

first, get the equation into standard form:  $\ ax^2+bx+c=0 $, where a, b, c are real #s

can you do that for me?

ell · Answer

4x^2 + 8x + 3 = 0...?

anonymous · Answer

where did that "+3" come from?  check your algebra...

ell · Answer

haha(: sorry, i mixed 2 prob. up. My fault:P 
+ 4 instead

anonymous · Answer

check it again... shouldn't it be " - 4" ???
so     $\ 4b^2 + 8b -4 = 0 $  
ok???

ell · Answer

mmkay, b/c of the positive and negative... got it. Thanks!

kenljw · Answer

4b^2 + 8b + 4 = 0
b^2 + 2b + 1= 0
quadratic equation
x^2 + bx +c = 0
x = (-b/2)(1 +- sqrt(1-c(2/b)^2)
Therefore
b=-1(1+-sqrt(0) = -1, -1
(b+1)^2 = 0

ell · Answer

yeah, ive got it now:) Thanks everyone for all your help@ Much appreciated! GBU!! <3 :)

anonymous · Answer

ok...
so can you identify these for me?
a = ???
b = ???
c =  ???

kenljw · Answer

yes my form is used in engineering