Question

factor the expression
c^2+4c+4

Answer 1

basically you have to find 2 numbers that

a) multiply to 4

AND

b) add to 4

Answer 2

those two numbers are 2 and 2 since 2+2 = 4, 2*2 = 4

so that's why c^2 + 4c + 4 factors to (c+2)(c+2)

Answer 3

A. (c + 2)^2



B. (c + 1)(c + 4)




C. (c^2 + 4)^2




D. the expression cannot be factored because it is prime.

Answer 4

I am confused
can you break it down for me again please

Answer 5

(c+2)(c+2) is the same as (c+2)^2

Answer 6

since something like x^2 means x times x

Answer 7

so would it be a? (c+2)^2 which is c^2+4

Answer 8

(c+2)^2 is NOT c^2 + 4

Answer 9

but yes, it is choice A

Answer 10

try using the quadratic formula. maybe she knows how to use that.

you will get one root c=-2. therefore you know c=-2 has multiplicity of 2 therefore we factor it as (c+2)^2

Answer 11

oh ok thank you, but how are they not the same if when you solve (c^2+2)^2 it makes 2x2+C times C and then simplify = 4+c^2

Answer 12

(c^2+2)^2 is not the same as (c+2)^2

Answer 13

expanding (a+b)^2=a^2+2ab+b^2 in general terms

Answer 14

oh

Answer 15

so if you expand (c+2)^2 you get c^2+2(c)(2)+2^2

=c^2+4c+4