Find S8 for the geometric series 3 + -6 + 12 + -24 +…
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OpenStudy (anonymous):
-96
-255
768
192
OpenStudy (anonymous):
@mathslover
mathslover (mathslover):
What is the common ratio here choco?
OpenStudy (anonymous):
the ratiois 3 again
mathslover (mathslover):
No. See I have ,
3 + (-6) + (12) + (-24) ...
3 * -2 = -6
-6 * (-2) = 12
12 * (-2) = -24
That is each number is getting multiplied by (-2) to get the another number of the series.
So common ratio here is (-2). Ok?
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OpenStudy (anonymous):
OK got it!
mathslover (mathslover):
Do you know the formula for getting S_n of a geometric series (infinite) ?
mathslover (mathslover):
^Not infinite. Its finite to 8.
OpenStudy (anonymous):
no thats the problem that Im having
OpenStudy (anonymous):
you there @mathslover
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mathslover (mathslover):
Yes, please wait.
OpenStudy (anonymous):
ok
mathslover (mathslover):
Formula : \(\cfrac{a(1-r^n)}{(1-r)} \)
mathslover (mathslover):
Put r = (-2) , a = 3 and n = 8 . Solve it now.
OpenStudy (anonymous):
ok
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OpenStudy (anonymous):
I got 257
mathslover (mathslover):
Try it again. It must be negative .
OpenStudy (anonymous):
ok -255
OpenStudy (anonymous):
?
mathslover (mathslover):
Right!
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