Question

Factor 3x^2-x-4 and 3x^2-12x+7 Please help...

Answer 1

what about the \(\frac{-b\pm\sqrt\Delta}{2a}\) formula?

Answer 2

We are using the distributive method....So yeahhh

Answer 3

just use it.

Answer 4

nd you do that how?

Answer 5

You have seen this formula before?

take 3x^2-x-4. \(a=3,b=-1,c=-4\Rightarrow \Delta = (-1)^2 - 4\times 3\times (-4) = 1 + 48 = 49\).
the two roots of the first polynomial are: \(\frac{-b\pm\sqrt{49}}{2\times 3}\) .

Answer 6

Omg I am so confused:/

Answer 7

a=3,b=−1,c=−4
is this part ok?

Answer 8

Yes

Answer 9

the general form of the polynomial of degree2 is ax^2+bx+c.
Yours is 3x^2-x-4. just read a=3,b=−1,c=−4

Then the formula is \(\Delta = b^2-4ac\).

Answer 10

Then put it in the fraction and you find two solutions because of the \(\pm\) .

this works if \(\Delta\ge 0\). if \(\Delta<0\) there's no real solution.

Answer 11

The answers are:
(3x − 1)(x + 4)

(3x + 4)(x − 1)

(3x − 2)(x + 2)

(3x − 4)(x + 1)
so it is one of those ^^^

Answer 12

what do you find for the roots of the polynomial?

Answer 13

I am so confused you just have to factor it

Answer 14

I found the answer now I need help with 4x^2+25x+6

Answer 15

ok.
two options,
- take all of the possibilities they offer, distribute and you will see which product gives your polynomial.
- use the forumla to find the roots (which are (1+7)/6=4/3 and (1-7)/6=-1)
therefore the factorization is \(a(x-x_1)(x-x_2) = 3(x-4/3)(x+1)\)

Answer 16

do the same.

Answer 17

Still confused

Answer 18

how did you do before?

Answer 19

x=-0.25,x=-6

Answer 20

Ok
multiply a and c if there is no GCF
then find numbers that multiply to get what a times c equals but when added equals B