Anyone can help me solve this question? [probability and statistic] The department received 4 calls every 20 minutes. Based on the time given, find the probability that the department will received not more than 3 calls.
do you know if this is Poison based? or not ...
and is there a table of graph of some sorts with this?
yes i know.. i already try but answer i get dfference from lecturer given..
fill me in on how youve tried to work it, becasue its not ringing any bells for me at the moment
mean = 4/20 = 1/5
\[P(x,u) = \frac{e^{-u}u^x}{x!}\] correct?
P(0,u)+P(1,u)+P(2,u)+P(3,u)
yes that a formula..then when it is less than 3.. we must get when P(X=0)+P(X=1)+P(X=2) right?
yes, but this is "not more than" 3, so we can have 0,1,2, or 3
then the answer different also.. the answer lectrer was 0.4335..
\[\frac{e^{-.2}.2}{0!}+\frac{e^{-.2}.2}{1!}+\frac{e^{-.2}.2^2}{2!}+\frac{e^{-.2}.2^3}{3!}\] \[e^{-.2}(1+.2+.02+..00133...)\] \[e^{-.2}(1.22133...)=.9999431...\] or have a messed it up someplace?
maybe a cumulative from 0 to 3?
what do u mean?
i have a poisonCDF function on my ti83, i was wondering if it would give something else but it still gives the .9999431...
oh so that have any other formula or what?
http://stattrek.com/probability-distributions/poisson.aspx the bottom of the page, example 1, is similar to this problem
may i knowthe question ask not more than 3 right? can u tell me more why u take 3 also?
because 3 is not MORE than 3
ok i think i get it now.. thanks a lot..
0 is not more than 3 1 is not more than 3 2 is not more than 3 3 is not more than 3 4 IS more than 3
i think the setup we did was correct, but we have to determine if the mean we are using is accurate
are we wanting to determine the probabiliy of the rate of x calls in 20 minutes? how do we determine the value of u?
i think the lambda was 4,, bcozthe question ask to find not more than 3 and do not have specific time at there.. but i'm not sure..
hmm, with 4, we do get the .43347...
i spose it was to be interpreted as 4 per 1 time interval ...
i think so.. but thank u for ur helping.. :)
good luck ;)
thanks..u too gud luck..
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