Question

How do i evaluate sopmething like this?It says Use even and odd properties of the trigometric function to find the exact value of the cos(-150 degrees).

Answer 1

firstly you have to know cos(-150)=cos(150)
After that ım rewriting 150 by using two numbers 90+60
It became cos(90+60)
when u write a sum as if that (90+x.270+y) you have to change the name of this function
e.g cos(90+60) = "sin"60
you can write other number right into paranthesis
so ,the result is :
\[\sqrt{3}/2 \]

Answer 2

thanks alot.but how did u get 90 and 60?i am lost from that line straight down

Answer 3

i know that it is \[\sqrt{3} \div 2 \] from memorization. but -150 is in the third quadrant, where cos is negative, therefor i believe you answer will be negative radical 3 over 2 but maybe vitas can confirm that for me