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solve by using double angle or half angle formula 1-cos4theta / sin4theta
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is that $$1-\frac{\cos4\theta}{\sin4\theta}$$?
i think it should be\[\frac{1-\cos 4\theta}{\sin 4\theta}\]
ok lets start with this:\[\cos4\theta=1-2\sin ^{2}2\theta\] \[\rightarrow 1-\cos4\theta=2\sin ^{2}2\theta\] \[\sin4\theta=2\sin2\theta \cos2\theta\] so then the equation will be:\[2\sin ^{2}2\theta \div 2\sin 2\theta \cos2\theta\] which will give: \[\sin2\theta \div \cos2\theta\] which is :\[\tan2\theta\] i think this is enough simplification..
thanks so much!
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