Question

what are the solutions to the nonlinear of equations below? check all that apply
x^2-y^2=4

x^2/2^2+y^2/2^2=1

A.(2,2)
B.(-2,-2)
C.(0,2)
D.(0,-2)
E. (2,0)
F.(-2,0)

Answer 1

what must x^2 and y^2 be equal to?

Answer 2

4

Answer 3

right

so what are the possible values of x and y in the list of options?

Answer 4

my mistake i meant to write x^2/2^2+y^2/2^2=1

Answer 5

ahhhh

Answer 6

so we have

x^2 - y^2 = 4

and

x^2 y^2
--- + --- = 1
2^2 2^2

right?

Answer 7

Correct

Answer 8

ok
simplify the second equation by multiplying thru by 2^2 ( = 4):

x^2 + y^2 = 4 ...................(1)

x^x - y^2 = 4 ....................(2)

now add (1) and (2)

what does that give?

Answer 9

** my typo
that x^2 in equation (2)

Answer 10

x^2-y^2 = x^2 + y^2 +4=4 ,that's what i got

Answer 11

is that right?

Answer 12

I just need the answers that could either be A,b,c,d,e, or f

Answer 13

when you add the y^2's are eliminated:- y^2 + - y^2 = 0
giving 2x^2 = 8

so now its easy to find possible values of x and y

Answer 14

would the final asnwer be 2,2?

Answer 15

E.
F.