Question

factor completely z^3-16

Answer 1

are u sure its z^3-16 ?
isn't it x^4-16 or z^2-16 ?

Answer 2

yeah

Answer 3

oh no it says z^3-16z

Answer 4

this makes it very easy!
z^3-16z
factor out the 'z' , what do u get ?

Answer 5

(z2-4) (z+4z) ?

Answer 6

no...how u got that ?
and take one step at a time, factoring out z from z^3-16z will give z (z^2-16)
got this? now can u factor z^2-16 ?

Answer 7

no but i need to factor it out so i get a 2 binomials that when you multiply them equals z^3-16z

Answer 8

i got the question, i asked u whether u got how,
z^3-16z=z (z^2-16)

Answer 9

\(\large z^2-16x = z^2\times z-16 \times z= z \times (z^2-16)\)
yes?

Answer 10

like for example i also had w^4-81 and the correct answer for that was (w^2-9) (w^2+9)

Answer 11

yes, thats correct, but you first need to get the form \(\Large a^2-b^2\)
to write it as \(\huge (a+b)(a-b)\)

Answer 12

and z^2-16 is in that form, right ? (16=4^2)