Suppose you have 50 feet of fencing to enclose a rectangular dog pen. The function A=25x-x^2, where x=width, gives you the area of the dog pen in square feet. What width gives you the maximum area? What is the maximum are?
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OpenStudy (anonymous):
maximum is the second coordinate of the vertex
the first coordinate of the vertex is always \(-\frac{b}{2a}\) which in your case is \(-\frac{25}{2\times -1}=12.5\)
OpenStudy (anonymous):
so your final answer is 12.5?
OpenStudy (anonymous):
in other words, in plain english, build a square
OpenStudy (anonymous):
your question has two parts:
a) find the width, and
b) find the area
OpenStudy (anonymous):
huh? I got A=25-x^2 using -b/2a and got -50/2-1 and got width equaling 25
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OpenStudy (anonymous):
yes that is the question
OpenStudy (anonymous):
the answer to the first part is the width and the length should both be \(12.5\)
OpenStudy (anonymous):
\(b=25\) not \(50\)
OpenStudy (anonymous):
so the maxium are would be.....
OpenStudy (anonymous):
12.5x12.5?
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OpenStudy (anonymous):
whatever \(12.5\times 12.5\) is
or whatever \(25\times 12.5-12.5^2\) is
either way, it is the same number
OpenStudy (anonymous):
thank you
OpenStudy (anonymous):
yw
OpenStudy (anonymous):
ok i have one more problem for you
OpenStudy (anonymous):
it is fairly easy
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