Question

find the number of ways 3 parties can be assigned to 3 of the 12 empty booths of a restaurant

Answer 1

@mathstudent55

Answer 2

Let

A, B, C be the 3 parties and D be considered an empty party or table

so one combo is ABCDDDDDDDDD

and another combo is ACDDDDDBDDDD

etc etc

Answer 3

soo the answer is ?? @jim_thompson5910

Answer 4

there are 12 P 12 = 12! = 479001600 ways to arrange the 12 positions....BUT...D repeats itself (there are 9 copies of D)

so you have to divide by 9! to get

479001600/(9!) = 479001600/362880 = 1320

Answer 5

so there are 1320 different ways to assign parties A, B, C to the 12 tables

Answer 6

thanks!