Question

how do you do this: What volume is occupied by 100.0 grams of chlorine gas (Cl2) at STP?

Answer 1

\[pV=nRT\\
\qquad\qquad\qquad n=\frac mM\\
pV=\frac mMRT\\
V=\frac{mRT}{pM}\]

Answer 2

where m =mass of chlorine = 100 g
R= gas constant T=Temperature=298K , P=1 atm and M is molecular weight of O2=18gram

Answer 3

M is molecular weight of Cl_2 = 2x35.45 g/mol=70.9 g/mol