Question

is Anyone willing to help ?

Answer 1

If you were to ask a question, more people could attempt to help.

Answer 2

(x2 + 13x + 40) ÷ (x + 8)

Answer 3

Factor your numerator and you will find that you have terms that will cancel.

Answer 4

idk how to do it.

Answer 5

\(x^{2}+13x+40\) What two things must multiply together to get the first term of \(x^2\)? Place them at the first thing inside the parenthesis ( )( )

Answer 6

(x+8)(x+5)?

Answer 7

Very good, now do you see a common factor in the numerator and denominator?

Answer 8

Nooo ? Im not Sure . X ?

Answer 9

The expression held within the ( ) can be treated as if it were a single term.

Answer 10

So if you have \(\frac{2*3}{2}\) it would be treated the same as \(\frac{x+8)*(x+5)}{(x+8)}\)

Answer 11

so x+8 is the common factor ?

Answer 12

Exactly, and what is anything over itself?\[\frac{1}{1}~or~\frac{2}{2}~or~\frac{(x+8)}{(x+8)}\]

Answer 13

1

Answer 14

Perfect! So your final answer is 1*(x+5)

Answer 15

Thankyou very Much (;

Answer 16

You are welcome. :)