Question

Simplify this:

Answer 1

\[\frac{ x ^{2}-9 }{ 4x-12 }-\frac{ x+3 }{ 2 }\]

Answer 2

\[\frac{(x+3)(x-3)}{4(x-3)}-\frac{x+3}{12}=\frac{x+3}{4}-\frac{x+3}{12}=\]
\[=\frac{(x+3)}{4}(1-1/3)=\frac{x+3}{6}\]

Answer 3

the answer i got here is 1/2

Answer 4

john's solution is correct

the answer is only 1/2 if x = 0

Answer 5

ok thanks