Use the limit process to find the area of the region between the graph of y=x^2+3 and the x-axis over the interval [0,2]? thanks for any brave respones

Question

anonymous · Answer

they give this triangle symbol which = 2/n

zarkon · Answer

$$\Delta x=\frac{2}{n}$$

anonymous · Answer

ok yeah thats the triangle but theres no x by it, thats why its confusing. Cant be delta x

phi · Answer

I would assume they mean delta x  (width of each rectangle)

zarkon · Answer

$$\lim_{n\to\infty}\sum_{i=1}^{n}f(x_{i}^{*})\Delta x$$

anonymous · Answer

ok that makes sense with the delta x, thanks phi.... Zarkon ok so im assuming thats the formula. How would I take my next step? and thanks guys i really preciate this

zarkon · Answer

are you using left or right hand endpoints...or something else.  (I'm assuming you are not using arbitrary partitions.)

zarkon · Answer

I would use $$x_{i}^*=a+i\Delta x$$

anonymous · Answer

The problem only gave me what i said above, I nerver even heard of using arbitrary partitions

anonymous · Answer

ok ill give it a try

zarkon · Answer

also I assume you meant y=x^2+3

anonymous · Answer

wow, yeah i did. My bad