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If the area of quadrilateral ABED= 6/5, find the area of triangle DEC BE=EF=FC
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@oldrin.bataku
Well given that relation we see the height of our triangle is just \(2/3\) that of the side \(BG\). We know the area of our rectangle is given by \((DC)(BG)\) and we can infer the area of our triangle is just \(\frac12(DC)(2BG/3)=\frac13(DC)(BG)\) so \(1/3\) of the area of our rectangle.
G?
@oldrin.bataku
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oops C not G
sorry I'm quite tired
@oldrin.bataku Oh, sorry for keeping you up with my questions, hah. So all those times you said G, you meant C right?
yep
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