Question

limit ((e^tan3x)-1)/ln(1+sin2x) as x->0

Answer 1

Is the limit :
\[\Large \lim_{x\to0}\frac{e^{\tan 3x}-1}{\ln(1+\sin 2x)}\]??

Answer 2

yes

Answer 3

@amistre64 @ahoward79 @alf123 @precal @skullpatrol @supercrazy92 @sofiasores @Shianne95 @Shikanu @thomaster

Answer 4

use L-hospital

Answer 5

\[\Large \lim_{x\to0}\frac{e^{\tan 3x}-1}{\ln(1+\sin 2x)}\]
Using L-Hospital,
\[\Huge \lim_{x \rightarrow 0} \frac{e^{\tan3x} \times \frac{3}{1+9x^2}}{\frac{1}{1+\sin2x}\times \frac{2}{\sqrt{1-4x^2}}}\]
Substitute x=0 now

Answer 6

You should get 3/2 most probably?

Answer 7

If you don't get anything hit me up.