Question

x^2+8x+15/x^2+9 divided by x+5/x-5
State any restrictions on the variables.


Options
A: x-5/x-3; x doesnt = +/-3, +/-5
B: 8x+5/3; x doesnt = +/- 3
C: x+3/x-5; x doesnt = +/-3, +/-5
D: x+3/X-3; x doesnt = +/-3

Answer 1

Plug em in this website http://www.wolframalpha.com/ #300

Answer 2

I tried that. It didnt process it the way it is supposed to be.

Answer 3

thanks for the response though. :)

Answer 4

Does the problem look like this ? http://www.wolframalpha.com/input/?i=%28x%5E2%2B8x%2B15%29%2F%28x%5E2%2B9%29+%2F+%28x%2B5%29%2F%28x-5%29+State+any+restrictions+on+the+variables.

Answer 5

yeah it kinda does but, the answer it gave is not one of my options. :(

Answer 6

All the options are wrong, I'm afraid. There could be a typo in your 4 options. I know this, because x can equal -5 but it can't equal +5 since if you plug +5 in the second term, you would get 10/0 which is undefined.

Answer 7

Thanks for the help. :)

Answer 8

the problem should be:

\[\frac{x^2+8x+15}{x^2\color{red}{-}9}/\frac{x+5}{x-5}\]which gives an answer that appears in the list.

Answer 9

so what answer would that be?

Answer 10

Factor both of the polynomials on the left. Cancel out any common factors, remembering which (if any) were factors in a denominator. Any denominator factors (whether canceled or not) need to be separately set equal to zero and solved for \(x\) — this gets you your restricted values because they are the points at which you would otherwise be dividing by 0, which is bad form and none of the cool math kids do it :-)