Given: h(x) = (1)/(2x + 3) ; g(x) = (x +1)/(x - 3)
1. (g of h)(x)
2. (h of g)((squareroot of 3) / 2)
3. 2/3 [(g of h)((squareroot of 2)/ 2)

Question

jhannybean · Answer

Wait a minute.... is it (1)/(2x+3)???

zzr0ck3r · Answer

g(x) says x-3

jhannybean · Answer

$$\large h(x) =\frac{1}{2x+3}$$$$\large g(x)= \frac{x+1}{x-3}$$1. $$\large g(h(x)) = \frac{\frac{1}{(2x+3)}+1}{\frac{1}{2x+3}-3}$$

jhannybean · Answer

Omg person's offline. It's too much to type up :|

jack1 · Answer

hahaha! after all that effort    ;(

anonymous · Answer

I'm sorry. Internet difficulties.

loser66 · Answer

to h(g(x)). At h (x) wherever you see x, replace by g(x) (the whole g(x)) and then simplify it.
Do the same with g(h(x)) . 
Your problem: |dw:1371988685338:dw|