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Given: h(x) = (1)/(2x + 3) ; g(x) = (x +1)/(x - 3) 1. (g of h)(x) 2. (h of g)((squareroot of 3) / 2) 3. 2/3 [(g of h)((squareroot of 2)/ 2)
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Wait a minute.... is it (1)/(2x+3)???
g(x) says x-3
\[\large h(x) =\frac{1}{2x+3}\]\[\large g(x)= \frac{x+1}{x-3}\]1. \[\large g(h(x)) = \frac{\frac{1}{(2x+3)}+1}{\frac{1}{2x+3}-3}\]
Omg person's offline. It's too much to type up :|
hahaha! after all that effort ;(
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I'm sorry. Internet difficulties.
to h(g(x)). At h (x) wherever you see x, replace by g(x) (the whole g(x)) and then simplify it. Do the same with g(h(x)) . Your problem: |dw:1371988685338:dw|
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