Question

The position of an object at time t is given by s(t) = -9 - 3t. Find the instantaneous velocity at t = 8 by finding the derivative.

Answer 1

You need to differentiate the equation.

Answer 2

\[s'(t)=-3\]

Answer 3

instantaneous velocity is the function of acceleration. The second derivative. \[\large \frac{d}{dx} [s(t)]\]

Answer 4

what is the derivative of this?

Answer 5

d/dx(-3)

Answer 6

No, intantaneus velocity is the first derivativo of position.

Answer 7

No, the answer is -3.

Answer 8

wait the differentiate thing... i need help with another type like this

Answer 9

hhh you're right! ok.

Answer 10

a few actually -.-

Answer 11

Find the derivative of f(x) = -10x2 + 4x at x = 11

Answer 12

-216

-196

-176

-363

Answer 13

I think so. Velocity is the rate of change of position, therefore, the instantaneous velocity is just the derivative of the position function. Since s(x) is a linear function the the derivative s'(x) is a constant (-3). So the answer is -3. That meanse that the velocity is always -3.

Answer 14

d/dx (-10x^2) + d/dx(4x then plug in x.

Answer 15

-10(11)^2 + 4(11)

Answer 16

yes you were right,instantaneous velocity is approximately equal to the rate of change of an object at a point.

Answer 17

no. no.

Answer 18

\[\large f'(x) = -10(2)x +4\]

Answer 19

-20(11) + 4

Answer 20

-216, got it! Thanks jhanny and ivan

Answer 21

Np.

Answer 22

Oh, I've got 2 more -.-

Answer 23

can I post a new Q and tag you two?

Answer 24

\[\frac{ d }{ dx }(-10x ^{2}+4x)=-10\frac{ d }{ dx }x ^{2}+4\frac{ d }{ dx }x=-20x+4\]

Answer 25

haha sure.