Question

state how many imaginary and real zeros the function has. x^4-8x^3+17x^2-8x+16

Answer 1

It's either 0 imaginary: 4 real
or 2 imaginary: 2real

Answer 2

\[x^4-8 x^3+17 x^2-8 x+16=(x-4)^2 \left(x^2+1\right) \]

Answer 3

so its all real?

Answer 4

A plot is attached.

Answer 5

is it 1 real and 3 imaginary?

Answer 6

someone please help

Answer 7

Do you have nay choices to go by just wondering

Answer 8

we can use Descartes rules of signs

Answer 9

yes. 0 real: 4 imaginary
1 real: 3 imaginary
2 real: 2 imaginary
4 real : 0 imaginary

Answer 10

x^4-8x^3+17x^2-8x+16

Answer 11

x=4 x=-i x=i

Answer 12

nevermind guys i got it

Answer 13

great ! you can strike off the first option cuz 3 imaginary is never possible for any polynomial, cuz imaginary roots come in pairs

Answer 14

you need to figure out the answer from last two... which u already figured out it seems :)

Answer 15

about 4

Answer 16

lol idk the ratio tho :P