Question

x^3+1;(x+1)

Answer 1

Is that division or what?
\[\frac{x^3+1}{x+1}\]

Answer 2

i think @SithsAndGiggles

Answer 3

asymptote at -1

Answer 4

In that case, @shay928, factor the numerator. As a sum of cubes, you have
\[a^3+b^3=(a+b)(a^2-ab+b^2)\]
In this case,
\[x^3+1=(x+1)(x^2-x+1)\]
Giving you
\[\frac{(x+1)(x^2-x+1)}{x+1}=\cdots\]