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Physics 22 Online
OpenStudy (anonymous):

If a metal ball suspended by a rod is at rest, which force is responsible for balancing the force due to gravity?

OpenStudy (souvik):

the tension in the rod balance the force of gravity..

OpenStudy (anonymous):

thank you :)

OpenStudy (anonymous):

do you know this one by any chance, A force of 15 newtons is applied to both Object A with a mass of 25 kilograms and Object B with a mass of 50 kilograms. What is true about the acceleration of Object A and Object B?

OpenStudy (souvik):

force =mass*acceleration or....acceleration = force / mass force is same in two cases.. mass of B is greater than that of A... so the acceleration of A is greater than that of B...

OpenStudy (anonymous):

is the acceleration of a greater by four times, half the acceleration of b, the same as accelertaion b, or twice the acceleration of b? do you know:o

OpenStudy (souvik):

acceleration of A=15/25 m/s^2 acceleration of B=15/50 m/s^2 that means acceleration of A is twice the acceleration of B

OpenStudy (anonymous):

omg, your freaking smart! (:

OpenStudy (souvik):

do you got the answer?

OpenStudy (anonymous):

yeah..

OpenStudy (anonymous):

lets test yor knowledge, do you know this one? In which direction does a bag at rest move when a force of 20 newtons is applied from the right?

OpenStudy (souvik):

it will move in the left direction...is not it?

OpenStudy (anonymous):

i put int the direction opposite of the directionn of the applied force but that waas wrong..

OpenStudy (anonymous):

the answer choices where, in the direction of the applied force in the direction opposite of the directionn of the applied force perpendicular to the direction of the applied force or in a circular motion?

OpenStudy (souvik):

in the direction of the applied force

OpenStudy (anonymous):

when i retake the test ill put that answer let see if its right..

OpenStudy (souvik):

is it?

OpenStudy (anonymous):

i have to wait for a while until the tecaheer unlocks the test cause i failed it..

OpenStudy (anonymous):

Lets do the next questions, look Which statement is true according to Newton's first law of motion?

OpenStudy (souvik):

bring it on...

OpenStudy (anonymous):

haha alright! ignore the top question, lets go for this next one. A car is moving at a constant speed along a straight line. Which statement is true about the forces acting on the car?

OpenStudy (anonymous):

a) the net force acting on the car from alll directions is zero. b) the net force acting on the car is graeter than the cars weight c) the net force acting on the car is in the direction of the cars motion d) the net force acting on the car is in the opposite of the cars motion

OpenStudy (souvik):

its a

OpenStudy (anonymous):

Ahh you know it, it was A..

OpenStudy (souvik):

:)

OpenStudy (anonymous):

An object of mass 5 kilograms is moving across a surface in a straight line with a speed of 3.5 meters/second. What amount of force would be required to keep the object in motion if you ignore the surface friction?

OpenStudy (souvik):

if there is no friction...no force is needed..

OpenStudy (anonymous):

My answer choices are 0 newtons, 17.5 newtons, 3.5 newtons or 5 newtons! So your saying 0 newtons right?

OpenStudy (souvik):

yes

OpenStudy (anonymous):

thank YOUUUUUUUU!

OpenStudy (souvik):

what are u doing?

OpenStudy (anonymous):

this tests online.. -.- and yhou?

OpenStudy (anonymous):

A car weighing 10,000 newtons is parked in a garage. Which statement is true about the forces acting on the car?

OpenStudy (anonymous):

a) the net force acting on the car from all directions is zero. b) the normal force acting on the car is less than the weigh's of the car c) the net force acting on the car is from the right of the car d) the normal force acting on the car is more than the weigh's of the car

OpenStudy (souvik):

a

OpenStudy (anonymous):

YES! When a net force of 17.0 newtons is applied to a dictionary placed on a frictionless table, it accelerates by 3.75 meters/secondÆ. What is the mass of the book?

OpenStudy (anonymous):

*3.75 meters/second^2

OpenStudy (souvik):

mass=force/acceleration calculate it ...

OpenStudy (anonymous):

Got it! With what magnitude of force does a ball of mass 0.75 kilograms need to be hit so that it accelerates at the rate of 25 meters/ secondÆ? Assume that the ball undergoes motion along a straight line. do i dot the samething here?

OpenStudy (souvik):

F=ma close this question put a new post

OpenStudy (08surya):

tension in the rod

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