Question

I am asked to solve 42=x^2-x
How do I solve this?

Answer 1

Notice how if you subtract 42 from both sides you get

\[x^2 - x - 42 = 0\]

Does that look like something familiar?

Answer 2

So in order to solve this, you need to set the right side equal to 0 by subtracting 42.

\[x ^{2}-x-42\]

Next you need to factor this.

The factors of -42 that equal -1 are 6 and -7, so

(x+6)(x-7)

Answer 3

*\[x ^{2}-x-42=0\]

Answer 4

Got it thanks for the help

Answer 5

You're very welcome :)