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Mathematics 18 Online
OpenStudy (anonymous):

Assuming that the octagon is regular, what is the area of the shaded region below? Use your calculator and round your final answer to the nearest hundredth.

OpenStudy (anonymous):

OpenStudy (anonymous):

@jim_thompson5910 A little help please? >.< Sorry to bug you~

jimthompson5910 (jim_thompson5910):

I'm sure you know the area of the square right?

OpenStudy (anonymous):

Yeah, A = L x W A = 11 x 11 A = 121

jimthompson5910 (jim_thompson5910):

ok what is the area of the octagon

jimthompson5910 (jim_thompson5910):

hint: the apothem will be used

OpenStudy (austinl):

\[A=\frac{1}{2} \times n \times s \times r\] n= number of sides s= length of side r= apothem

OpenStudy (anonymous):

292.16 is what I got.

jimthompson5910 (jim_thompson5910):

austinL has the right formula

OpenStudy (austinl):

Unfortunately, that is not the same answer that I got.

OpenStudy (anonymous):

If his formula is correct, the answer should be 584.32 square units.

OpenStudy (austinl):

But that is including the area of the square that you do not need.

jimthompson5910 (jim_thompson5910):

it is correct formula for the area of the polygon think about it like this: break the octagon into 8 triangles |dw:1372813369235:dw|

jimthompson5910 (jim_thompson5910):

each triangle is congruent and each triangle looks like this |dw:1372813444716:dw|

jimthompson5910 (jim_thompson5910):

so the area of this triangle is (1/2)*r*s there are n of these triangles, so multiply this by n to get (1/2)*n*r*s

OpenStudy (anonymous):

849.92 is what I have now then.

jimthompson5910 (jim_thompson5910):

Area of Shaded Region = (Area of Octagon) - (Area of Square)

OpenStudy (austinl):

\[A_{shaded region}=A_{octagon} - A_{rectangle}\] \[A_{shaded region}=(\frac{1}{2} \times n \times s \times r) - (l \times w)\]

OpenStudy (anonymous):

607.92 is what I have now. >.<

jimthompson5910 (jim_thompson5910):

what did you get for the area of the octagon?

OpenStudy (anonymous):

88.

jimthompson5910 (jim_thompson5910):

that's not correct

jimthompson5910 (jim_thompson5910):

use the formula given above

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