Question

In a random sample of 50 undergraduate students at a college, it was found that 44 students regularly access social networking websites from their college library. What is the margin of error for the true proportion of all undergraduates who access social networking sites from their college library? PLEASE HURRY

Answer 1

i believe you are looking for sqrt(pq/n)

Answer 2

i have no idea how to even use that... do you know or no

Answer 3

im giving you guidance. we are not running a free answering service here.

Answer 4

p and q generally represent the proportion of success to failure; and n is the sample size

Answer 5

so i just plug the numbers in?

Answer 6

lets define them first :)

it tells us that we have 50 students, and 44 are our success rate:

p = 44/50

can you tell me from that what our q (our fail rate) is?

Answer 7

.88?

Answer 8

if you want to go that route:

then p = .88, q must equal 1-.88

Answer 9

one of the answer choices is .92

Answer 10

and that is the only one between 1-.88

Answer 11

we havent reached the final result yet, so its best not to try to jump the gun

Answer 12

oh i just thought thats what you meant..

Answer 13

p = .88, q = .12, and n = 50

from this we can calcuate: sqrt(pq/n)

Answer 14

ohhhh i see

Answer 15

so 0.1056 x 50?

Answer 16

.1056/50

Answer 17

*

Answer 18

sqrt(.88*.12/50) = about .046

Answer 19

http://www.wolframalpha.com/input/?i=sqrt%28.88*.12%2F50%29

Answer 20

i got .02112

Answer 21

oh nevermind, thank you (:

Answer 22

your welcome