Question

x+3y-z=10 2y-z=0 3z=18 find solution

Answer 1

Didn't get your question?

Answer 2

As far as I understood, z=6, y=3, x=7

Answer 3

How? :o

Answer 4

3z = 16
z =6
substitute z=6 in 2y-z=0, you get y = 3.
Then substitute the values of x and y in x+3y-z=10
you get x =7

Answer 5

3z=16
z= 6 :o which table are you using :o

Answer 6

Yeahh BTW you are right :) I agreee :D

Answer 7

sorry, it was 18.
I am feeling sleepy here,night 12.30. So,there was a mistake.

Answer 8

Hahaha okay no problem :)