Question

got statistic test tonight, help !
a sample space is composed of 3 outcomes , A,B and C .Outcome B is twice as probable as A and C is twice as probable as B. Find the probabilities of the events of A,B and C

Answer 1

remember in probabilities, the sum should always be 1

Answer 2

so you have A + B +C = 1

now just express A and C in terms of B then solve

Answer 3

but im confuse.. what does it mean by Outcome B is twice as probable as A and C is twice as probable as B.???

Answer 4

P(B)=2*P(A)=1/2 * P(C) @Ika_Kim

Answer 5

so 1/2*P(B)+P(B)+2*P(B)=1, now you can find your P(B) and hence the others

Answer 6

does my response worth a medal?

Answer 7

urm...i dont understand...sorry....

Answer 8

As a said, B is twice as possible as A literally translates to P(B)=2*P(A), do you understand this?

Answer 9

and based on the idea above, we also have P(C) =2*P(B),

Answer 10

ok i got that

Answer 11

then ???

Answer 12

You know that P(A)+P(B)+P(C)=1, do you?

Answer 13

yes i do.. so... we convert them to the same term ?

Answer 14

so you can treat P(A),P(B),P(C) as three variables and the three equation appeared before are the ones to solve, and I assume you can solve a system of linear equations with three variables

Answer 15

thx @xlegendx , you just boosted my score by 1

Answer 16

owhh ok. i got it !!!! thanks guys !!!!!!!! :D