Question

s

Answer 1

Was I tagged?

Answer 2

yes, It's me.I need your help

Answer 3

Hold on. I'll do only one.

Answer 4

That's for the first one.

Answer 5

how to get that slope?

Answer 6

for the absolute value function it is translate 2 units to the right so it becomes abs(x-2) and it is translate 2 units down so it is abs(x-2) -2
i dont have the simbols for absolute value so i wrote abs()

Answer 7

Prime Ralph I am sorry. But you are incorrect. The slope is wrong and it maeks no sense

Answer 8

But julian when I plug in the points, it does not work. I thought the same as you but plug in some points

Answer 9

I'm feeling sleepy. That's why I wanted to do only one.

Answer 10

yes i m working on th slope

Answer 11

1 minute

Answer 12

okay

Answer 13

Prime Ralph, plug in some ponts. It does not work at all.

Answer 14

THanks for the help but it does not make sense and if you plug in any number, the y does not relate to what is shown on the graph.

Answer 15

Looks like I should hit the bed.
Good luck.

Answer 16

Thanks for the help at least :)

Answer 17

ok u can see on the graph that the slope is (2/8) so the equation becomes
(2/8)abs(x-2) -2

Answer 18

wait how did you find the slope for that one?

Answer 19

u can see it changes 2 units in the y axis and 8 units in the x axis

Answer 20

isn't it then -1/4?

Answer 21

yes but the absolute value its defined by 2 lines

Answer 22

oh so its 1/4

Answer 23

okay thanks.
And what aobut for the 2nd problem?

Answer 24

(1/4)(x-2) -2
and
(-1/4)(x-2) -2

Answer 25

huh and?

Answer 26

its just 1/4(x-2) -2

Answer 27

?

Answer 28

and with negative slope too
u must graph both functions
one defined (-inf, 2)
and the other defined (2, inf)

Answer 29

ok lets do the second
u have that the graph open downward so it bevomes -x^2
it is translate to the left 2 units so it becomes -(x+2)^2
and it is translate downwar 1 unit so it becomes
-(x+2)^2 -1
now we must see if that equation agrre with some points on the graph

Answer 30

since its abslute value, aren't both included since its always positive?

Answer 31

the abosolute value it is not always positive fort example f(x)=abs(x) -5 plug 1 there and u have f(1) = 1 -5 = -4

Answer 32

the graph of -(x+2)^2 -1 agree with the vertex and it opens downward but dont agree with the y intercept we must multiply it by someting

Answer 33

okay makes sense

Answer 34

ok if we multiply it by (1/2)we get
-(1/2)(x+2)^2 -1
and that agree with the graph

Answer 35

okay let me check :)

Answer 36

how do you find the 1/2 of a parabola?

Answer 37

jajaj i dont know that part at first i just multiply it by something but i will find a algebraic way of do that

Answer 38

okay

Answer 39

cause I am so confused. Also why is it negative?

Answer 40

it is because it opens donwward

Answer 41

i though u was following me

Answer 42

okay. I get it!!! just the 1/2 I dont see how u got?

Answer 43

i dont know either let me see

Answer 44

okay

Answer 45

i though that i get it 1 min

Answer 46

okay take your time :)

Answer 47

ok so we must multiply by a constants lets say (k) we must find the value of that constant to do that take for example a pint on the graph for exanple the y intercept (0, -3) and replace that point in the equation
y= -k(x+2)^2 -1
-3 = -k(x+2)^2 -1
solve that equation and u will find that k = 1/2

Answer 48

sorry
-3 = -k(0+2)^2 -1

Answer 49

solve that equation and u will find that k = 1/2

Answer 50

oh. Thanks so much. I appreciate it.

Answer 51

im confused