PLEASE HELP!!! Let f(x) = x2 + 3x - 4 and g(x) = x + 5. Find f(x) • g(x).
a) x3 + 3x2 + 16x - 20 b) x3 + 5x2 + 14x - 20 c) x3 + 8x2 + 11x - 20 d) x3 + 9x2 + 19x - 20
So, you just multiply the functions, right? Let's get to it :) \[\Large (x^2 +3x - 4)(x+5)\]
Could you simplify this?
Okay, hint, we could distribute the entire \(\large (x^2 + 3x- 4)\) over the \(\large (x+5)\) Thus giving us... \[\Large x(x^2 + 3x -4)+ 5(x^2 + 3x - 4)\] And now, just two more distributions and then combining like terms :)
to bad i cant show you what i worked out... i did it on paper
Well, you could tell me what you did :)
final answer i got was a after combining like terms. a) x3 + 3x2 + 16x - 20
Well, unfortunately, that's not the correct answer :)
Let's find out together what IS the correct answer, shall we? :) Come now... Distribute the x over the terms inside the parentheses. \[\Large \color{red}x\color{green}{(x^2 + 3x -4)}+ 5(x^2 + 3x - 4)\]
oh i didnt distriubute
So, now you can distribute, what becomes of that coloured bit? :)
ya bro sorry im lost
Distribute? Example... \[\Large \color{red}{2x^2}\color{green}{(x - 7)}\] You just multiply the one term outside with EACH AND EVERY term inside, like... \[\Large = \color{red}{2x^2}\cdot \color{green}x \ \ - \ \ \color{red}{2x^2}\cdot\color{green}{7}\]\[\Large = \color{blue}{2x^3 - 14x^2}\]
thanks bro! i got it the answer is c) x3 + 8x2 + 11x - 20
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