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Mathematics 20 Online
OpenStudy (anonymous):

PLEASE HELP!!! Let f(x) = x2 + 3x - 4 and g(x) = x + 5. Find f(x) • g(x).

OpenStudy (anonymous):

a) x3 + 3x2 + 16x - 20 b) x3 + 5x2 + 14x - 20 c) x3 + 8x2 + 11x - 20 d) x3 + 9x2 + 19x - 20

terenzreignz (terenzreignz):

So, you just multiply the functions, right? Let's get to it :) \[\Large (x^2 +3x - 4)(x+5)\]

terenzreignz (terenzreignz):

Could you simplify this?

terenzreignz (terenzreignz):

Okay, hint, we could distribute the entire \(\large (x^2 + 3x- 4)\) over the \(\large (x+5)\) Thus giving us... \[\Large x(x^2 + 3x -4)+ 5(x^2 + 3x - 4)\] And now, just two more distributions and then combining like terms :)

OpenStudy (anonymous):

to bad i cant show you what i worked out... i did it on paper

terenzreignz (terenzreignz):

Well, you could tell me what you did :)

OpenStudy (anonymous):

final answer i got was a after combining like terms. a) x3 + 3x2 + 16x - 20

terenzreignz (terenzreignz):

Well, unfortunately, that's not the correct answer :)

terenzreignz (terenzreignz):

Let's find out together what IS the correct answer, shall we? :) Come now... Distribute the x over the terms inside the parentheses. \[\Large \color{red}x\color{green}{(x^2 + 3x -4)}+ 5(x^2 + 3x - 4)\]

OpenStudy (anonymous):

oh i didnt distriubute

terenzreignz (terenzreignz):

So, now you can distribute, what becomes of that coloured bit? :)

OpenStudy (anonymous):

ya bro sorry im lost

terenzreignz (terenzreignz):

Distribute? Example... \[\Large \color{red}{2x^2}\color{green}{(x - 7)}\] You just multiply the one term outside with EACH AND EVERY term inside, like... \[\Large = \color{red}{2x^2}\cdot \color{green}x \ \ - \ \ \color{red}{2x^2}\cdot\color{green}{7}\]\[\Large = \color{blue}{2x^3 - 14x^2}\]

OpenStudy (anonymous):

thanks bro! i got it the answer is c) x3 + 8x2 + 11x - 20

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