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OpenStudy (anonymous):
A transformation such that if P is on l,then P coincides with P' , and if P is not on l, then l is the perpendicular bisector of ( line segment PP') ????
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OpenStudy (accessdenied):
Let's see... "If \(P\) is on \(l\), then \(P\) coincides with \(P'\)." "If \(P\) is not on \(l\), then \(l\) is the perpendicular bisector of \(\overline{PP'}\)." I think it would be easier to see this visually. |dw:1373328779976:dw|
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