Question

1. AD= 12 and CD=8 find BD
***************metal****************

Answer 1

weres the diagram

Answer 2

hold up girl ill show it in a bit
problem 36

Answer 3

diagrem next to it

Answer 4

@jim_thompson5910 help me please :)

Answer 5

u have to get the altitude ....

Answer 6

let x = length of BD

AD/BD = BD/CD

12/x = x/8

12*8 = x*x

96 = x^2

...
...
...

x = ??

Answer 7

??\\

Answer 8

if x^2 = 96, then what is x

Answer 9

x-48

Answer 10

no

Answer 11

i mean x=48

Answer 12

you don't divide both sides by 2

Answer 13

you take the square root of both sides (to undo the square) and you simplify as much as possible


\[\large x^2 = 96\]


\[\large x = \sqrt{96}\]


\[\large x = \sqrt{16*6}\]


\[\large x = \sqrt{16}*\sqrt{6}\]


\[\large x = 4\sqrt{6}\]

Answer 14

thnxxx'

Answer 15

np

Answer 16

@jim_thompson5910 can you check the diagram and help me on 38 please

Answer 17

same idea, but now

AD/BD = BD/CD

sqrt(2)/x = x/sqrt(2)

sqrt(2)*sqrt(2) = x*x

(sqrt(2))^2 = x^2

x = ???

Answer 18

????

Answer 19

if x^2 = (sqrt(2))^2

then what is x

Answer 20

x = ??? means I want you to fill in the blank

Answer 21

sorrry but i dont get it at all

Answer 22

a square root undoes a square, so squaring a square root makes it go away

Answer 23

this is why (sqrt(2))^2 = 2

so

x^2 = 2

x = sqrt(2)

Answer 24

by geometric mean property
\[BD^2=AD \times CD=12\times 8\]
\[BD^2=96 \rightarrow BD = \sqrt{96}=4\sqrt{6}\]

Answer 25

thnxxxxxx all of u