Question

three non zero numbers a,b,c are in ap.Increasing a by 1 o increasing c by 2 the number becomes in gp then b equals to

Answer 1

what means o there ?

Answer 2

it's or

Answer 3

ohhh --"

Answer 4

a, b, c --> AP
b-a = c-b or
b = (a+c)/2 ... (1)

a+1, b, c ---> GP
b/(a+1) = c/b or
b^2 = c(a+1) ... (2)

a, b, (c+2) ---> GP
b/a = (c+2)/b or
b^2 = a(c+2) ... (3)

(2) = (3),
let's see what u get then .......

Answer 5

here a =1/2

Answer 6

it's not cuming

Answer 7

how you get that ? just guessing ?

Answer 8

wait it's cuming as c=2a

Answer 9

yup. that's right

Answer 10

and we get it as b=3/2 a

Answer 11

correct again

Answer 12

then what

Answer 13

b = 3/2 a ---> a = 2b/3 , agree ?

Answer 14

c = 2a
because a = 2b/3, then the c can rewriten as
c = 2a = 2(2b/3) = 4b/3

Answer 15

now you have a and c in b

Answer 16

ryt

Answer 17

subtitute them to one of (2) or (3) equation

Answer 18

to (1) equation works too

Answer 19

which one do you want :)

Answer 20

that's not cuming

Answer 21

hmm... yeah the 1st equation doesnt work
try use the 2nd equ :
b^2 = c(a+1)

now subtitute the value of a = (2b)/3 and c = 4b/3

Answer 22

got it ?

Answer 23

no

Answer 24

b^2 = c(a+1)
b^2 = (4b)/3 * (2b/3 +1)
simplify then solve for b

Answer 25

got it

Answer 26

really, what is it

Answer 27

12

Answer 28

smart :)

Answer 29

one more question 2 u

Answer 30

why to me --"

Answer 31

bcuz u hve that intelligence to solve it