Question

When HSO4- disassociates in water, it is a reversible reaction. Is it correct to say that "in this reaction HSO4- disassociates to H+ and SO4- and H+ and SO4- react to form HSO4-"

Answer 1

yes :)

Answer 2

HSO4−(aq) ⇌ SO42−(aq) + H+(aq)

Answer 3

Yes, so it's fine if we say that to explain what's happening in the reaction?

Answer 4

bcoz HSO4 - is a weak acid compared to H2SO4

Answer 5

When H2SO4 is dissolved in water, the first proton is assumed 100% dissociated because H2SO4 is a strong acid. After H2SO4 dissociates, we have H+ and HSO4− present. HSO4
− is a weak acid and can donate some more protons to water

Answer 6

what do u mean by Bed potato @bedpotato LOL:)

Answer 7

Like couch potato, but BED potato.

Answer 8

haaa haaaa LOL :) :P did u get the answer by the way

Answer 9

Yes i did. Thanks.

Answer 10

yw :)

Answer 11

Sulfuric acid is a diprotic meaning it can release 2 protons (H+ ions) when it ionises. So it undergoes disassociation in two steps:

The first one:
H2SO4(aq) + H2O(l) -----> H3O+(aq) + HSO4-(aq)

In the above equation, it has released one of its H+ ions. However, since is releases two, you have the equation: (this is the second step)
HSO4-(aq) + H2O(l) <-------> H3O+(aq) + SO4^2-(aq)
In this equation it releases the other H+ ion.
HSO4- will act as a weak acid in water and donate a proton.
Since it's acting as a weak acid, it doesn't donate all of its protons (only partially disassociates). That's why the equation is reversible, HSO4- can disassociate to H+ and SO4- and H+ and SO4- can react to form HSO4-.

Answer 12

LOL what is this :) NOW

Answer 13

you knew answer lol

Answer 14

I know. I wanted to make sure I was right.

Answer 15

haaa haaa now ur sure ????