Question

Y/27=3/Y
WHAT IS THE LARGEST POSSIBLE VALUE OF Y THAT WOULD SOLVE THE EQUATION ABOVE?

Answer 1

\[{y\over27}={3\over y}\]\[y\times y=27\times3\]\[y^2=81\]\[y=9\]
\[{9\over27}={3\over9}\]\[{1\over3}={1\over3}\checkmark\]

Answer 2

so \(y=9\) :)

Answer 3

omg ur so frucking smart!!!
and i feel like a dumbarse cuz i put 9 and my stupidity just told me it not the right answer

Answer 4

lol no probs :)

Answer 5

need anymore? :)

Answer 6

umm nope

Answer 7

all good ^^

Answer 8

alright well it was nice working with you, good luck with the SAT :)